in how many ways can 9 people be seated if 3 ch... - JAMB Mathematics 2009 Question
in how many ways can 9 people be seated if 3 chairs 3 chairs are available
A
720
B
504
C
336
D
210
correct option: b
\(\frac{n!}{n - r!}\) = \(\frac{9!}{9 - 3!}\)
= \(\frac{9!}{6!}\)
= 9 x 8 x 7
= 502
= \(\frac{9!}{6!}\)
= 9 x 8 x 7
= 502
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